Given a non-empty array of integers nums[], every element appears twice except for one. Find that single one.

Input: nums = [2,2,1]

Output: 1

Example 2:

Input: nums = [4,1,2,1,2]

Output: 4

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public class Main {

public static int SingleNumber(int[] nums)//2,2,1 {

int result = 0;

for (int num : nums) {

result ^= num;

}

return result;

}

public static void main(String[] args) {

int[] nums1 ={2, 2, 1};

System.out.println(SingleNumber(num1))//1;

}

}